Loading Diown subs.
 

Say one has 6 8ohm svc subs and he loads them down, what will be the final load? Parallel or series?

Do the same for 10 8ohm svc subs as well.:smokin:

Let's see everyone's answers.

when you say 8" do you mean 8ohm?

The North American keyboard equivalent of ohm is W

6 8Ω speakers in series is 48Ω
in parallel it's 1.33Ω

10 8Ω speakers in series is 80Ω
in parallel it's 0.80Ω

Unless I'm misunderstanding your question.

sorry, 8 ohms svc subs

If i want an ending load of 4ohms or close to it, how many subs would I use and how would it be done? If at all it is possible?

I can get close, let me do the math and I'll draw up a sketch

6 8Ω speakers

https://dl.dropbox.com/u/800458/Explan.jpg

~5Ω total load.


For 10 speakers it's the same idea, but instead of 3 parallel in each group, you have 5.
Total load ends up being 3.2Ω

Best case would be to use 8 speakers in this configuration, with groups of 4. Total load is 4Ω

Brad I like your paint skills.

I like your butt.

Long time Kirby :P

Totally forgot about that site bro. thanx for the information everyone.