passive
allrighty its about time i ask this question
i understand how to figure out nominal impedance for single drivers (say 2 12s with duel coils)
when you put say a mid and tweet on an amp, does the amp see the tweet sepret from the mid? so say they are each 4 ohm drivers, the amp sees a consistant 4ohm load over the spectruim. or would i add them so it sees an 8 ohm load or 2ohm?
i understand how to figure out nominal impedance for single drivers (say 2 12s with duel coils)
when you put say a mid and tweet on an amp, does the amp see the tweet sepret from the mid? so say they are each 4 ohm drivers, the amp sees a consistant 4ohm load over the spectruim. or would i add them so it sees an 8 ohm load or 2ohm?
so it sees one load not each individual driver
say that i had a 100watt amp (just for easy numbers)
my tweet will then see the 100watts, and the mid the same 100watts
or do i divide the power up as i would running 2 drivers off the same channel with no crossover so each would get 50watts?
say that i had a 100watt amp (just for easy numbers)
my tweet will then see the 100watts, and the mid the same 100watts
or do i divide the power up as i would running 2 drivers off the same channel with no crossover so each would get 50watts?
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Originally posted by Dukk:
^ Oh? explain. [img]smile.gif[/img]
^ Oh? explain. [img]smile.gif[/img]
1. Power Compression - different drivers have different characteristics here, some will suffer from it earlier than others.
2. Impedence - this could actually be taken care of with a carefully designed crossovers, but ot would more than likely be that both drivers (mid and tweet) would exhibit different impedence curves over their operating bandwidth
Those are a couple that come to mind, I could think of more I am sure.
Even if the crossover was designed in such a way that the power was split 50/50, it would only hold true into a nominal impedence.
The operating impedence of a driver will vary depending the part of the musical spectrum it is currently playing.
The mid could be playing a low note which will make the driver see 1 ohm while the tweeter could be playing a note that will present an 8 ohm load, therefore the 50/50 ratio is gone and the mid is now seeing more of the avaliable power.
Would this be true?
The operating impedence of a driver will vary depending the part of the musical spectrum it is currently playing.
The mid could be playing a low note which will make the driver see 1 ohm while the tweeter could be playing a note that will present an 8 ohm load, therefore the 50/50 ratio is gone and the mid is now seeing more of the avaliable power.
Would this be true?
this question came to me when i though about ordering speaker seaprets, such s as a ribon tweet, dome mid, and a 8 woofer, and building my own home speakers, if i built the passive so that each part is only reciving a bandwidth that the other drivers are not seeing i was wondering how to figure out nominal impedances and such.
so in the above example say each driver is has a nominal impedance of 8ohms, the crossover is desined so that the drivers do not share a frequancy, would my nominal impedance be 8 ohms?
and therefor each driver is seeing equal power (at rated nominal impedance)?
so in the above example say each driver is has a nominal impedance of 8ohms, the crossover is desined so that the drivers do not share a frequancy, would my nominal impedance be 8 ohms?
and therefor each driver is seeing equal power (at rated nominal impedance)?
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would the tweeter not see the 100 watts through its bandwidth, and the midrange through its bandwidth, obviously there will be potential impedence variances between the midrange and the tweeter, but i dont believe that the power would get split 50/50 as the amplifier puts out 100 watts through the audible bandwidth, correct


