I am tring to use the Alpine I-personalize to fine tune my deck I understand gain and frequency I have set those but its asking me to set the slope

I have my gain set to "0" and Frequency set 31.5db (this example is for my sub) What should I set my slope at and what does it mean??

[img]graemlins/beer.gif[/img]

 

Does it give you a choice of 12/18/24? If so that would be the crossover slope, in db's/octave. http://www.bcae1.com/xovrslop.htm Someone else on here can explain this better than I can I am sure......

 

Ok from what I understand the slope is the point where you start to gradually cutout unwanted frequencies. The best way to describe this, that i can think of is to see an octave as a double of frequency. Like 40 to 80 hertz is an octave so is 300 to 600hz and 1000 to 2000hz and so on... you get the picture.
As for the db per octave part that is the amount of cutoff starting at your crossover point. So the higher the db the greater the cutoff. If your crossover was set at 200hz at 24 db per octave, you would have 24 db less signal at 100 hz.
Im also sure that someone here can put it a lot better than i did, but this should help you understand [img]graemlins/thumb.gif[/img]

 

Crossover slope is how much SOUND is filtered out ABOVE or BELLOW the CROSSOVER POINT...the steeper the SLOPE(24db) the less FREQUENCIES will be heard BELOW THAT X-over point.

If you pick a X-over Freq @ 100HZ--@--6db slope will allow FREQUNCIES DOWN to about 30HZ to be heard.(BARLEY).

If you pick same X-over freq @ 100hz--@--24db slope it will ATTENUATE MORE FREQUENCIES and nothing below about 80HZ would be heard. [img]graemlins/bump.gif[/img]

 

008, in your examples are you talking about the "roll off effect" that can still be heard beyond the X over point?

 

ok...its really not that complicated people...think about this for a second..."dee-bee per octave"

ie. a 12 db/oct high pass crossover @ 100hz means that at 50 hz, the signal will be 12 db quieter then at 100hz.

if this was a 24 db/oct slope. then 50 hz would be 24 db quieter, and 25 hz would be 48 db quieter then 100hz.

If it was 12 db/oct low pass x-over at 100 hz, then 200 hz would be 12 db quieter then 100 hz.

[ April 05, 2004, 03:42 PM: Message edited by: Orion_95 ]

 

Slope is determined by decibels/octave.

In terms of voltage the formula is

20 log vout/vin

-3db is equall to when .7071% of the input voltage reaches the output.

It is also the half power point.

For example a simple 6db/octave high pass filter
(capacitor) set for 100hz, 4 ohms

The amp puts out 20volts.

Impedance of 4ohm cap in series with 4 ohm speaker equalls Z=5.65ohms

20v/5.65 ohms=3.53 amps

3.53 amps* 4 ohms=14.15 volts

20 log 14.15/20 volts= -3db

At 50 hz speaker 4 ohm , cap is now 8ohm

Z=8.94

20/8.94ohms= 2.23amps

2.23 ampsx 4ohms=8.94 volts

20 log 8.94/20=-6.99 db

 

I am amazed that after Orion 95's explaination that it inst clear enough.


Why the replys after? [img]graemlins/dunno.gif[/img]

 

Orions explanation was very clear and understandable to me..