RyanR

Hi,

I currently have an Alpine MRP-M650 amp and I just bought an Alpine Type R to replace my blown one but the new one is 2ohms and the old one is 4 ohms. Both are dual voice coils so I was wondering if I could still hook up my new one and how would I do it or do I need to get one that is 4 ohms?

Thanks

JohnnyRock1588

iTrader: (22)

when in doubt...

http://www.rockfordfosgate.com/Suppo...x#wiringwizard



or in your case since that alpine is not 1 ohm stable, wire to 4 ohm

RyanR

Great!!! Thanks. So would this essentially be the same as running a dual 4 ohm in parallel?(the second picture) or no...that would have a 2 ohm load right? Is there a way to make a DVC 2 ohm sub see a 2 ohm load? My amp does 600rms at 2 ohms and 400rms at 4 ohms so I want to get the most out of it. Please correct me if I'm wrong because I am new at this.

Dukk

No. You picked up the wrong impedance - or rather the DVC4 is a better choice for your amp. If you have the option, exchange the sub.

JohnnyRock1588

iTrader: (22)

No prob Ryan!

2ohm final load will get the most out of your amplifier but for now if you cant exchange the sub like dukk said then running it at 4 ohms will be fine.

unless you get another dual 2 ohm sub you will not be able to make 2 ohm final load.

RyanR

Alright, thank you both. I kind of expected that is what I would have to do.

JohnnyRock1588

iTrader: (22)

ryan just run it at 4ohms it will still get enough power as you wont notice the difference between 200watts on a sub. not audibly or musically anyways.
save yourself the money of buying another sub and box ect.

RyanR

Wasn't a big deal, I just brought it back and exchanged it but its still good to know thanks.

audio1der

Don't forget; that would be 2 woofers sharing 600W, resulting in each woofer seeing only 300w instead fo the single sub seeing 400w. Just food for thought. I recognize the increased cone area would likely overcome that issue, but many of us who run a single woofer have space constraints to begin with, so there's another factor.