Lspade

I am so sick of trying to figure out why two 4ohm subwoofers connected to an amp gives an over all load of 2ohms. 4 ohms plus 4 ohms equals 2 ohms??????? Can someone explain to me wut is up with this. I don't care if you go into dividing and multiplying amperes and volts and watts. I understand most of that stuff but i would really like to understand why 4ohms plus 4ohms equals 2ohms.

SweetnLow91SC

Well.... 4ohms is a resistive load, when you have two 4 ohms resister or subs in parellel the resistance goes down...... by half = 2 ohms which is closer to a short as resistance goes down.

2 8's AKA Jeepbeats

iTrader: (19)

In a series circuit the resistance adds directly (4 ohms + 4 ohms = 8 ohms), with parallel circuits you invert the two that you are ading together, then invert them again(4 ohms + 4 ohms actually equals 1/4 + 1/4 = 2/4 then you invert it, so that the 4 is over the 2, which equals 2). Ohms law. http://www.angelfire.com/pa/baconbacon/page2.html

[ October 20, 2005, 05:20 PM: Message edited by: 2 8's AKA Jeepbeats ]

Lessy

Series: Rt(total) = R1 + R2 + R3 +...

ex.
Rt = 4ohm + 4ohm = 8ohm

Parallel: 1/Rt = 1/R1 + 1/R2 + 1/R3 +...

ex.
1/Rt = 1/4ohm + 1/4ohm = 2/4
Rt = 4/2 = 2ohm

[ October 20, 2005, 05:31 PM: Message edited by: Lessy ]

Lessy

and if you wanna do series-parallel, calculate series first

ex. 2 dual 4ohm subs

sub 1
4 + 4 = 8

sub 2
4 + 4 = 8

then, 1/Rt = 1/8 + 1/8 = 2/8
Rt = 8/2 = 4ohm

[ October 20, 2005, 06:04 PM: Message edited by: Lessy ]