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Tell me this will work!!!

Old Jan 12, 2004 | 02:01 PM
  #1  
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http://www.kenwood.ca/kwcgi/kww001?c...item=KAC-8101D

Will this work for my 4ohm 250 watt rms subs. I can get this amp for 100 dollars. If this is the right model anyway. How many other 1000 watt kenwood amps are there besides the other one on the website?
Old Jan 12, 2004 | 02:13 PM
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how many watts will this give each sub?
Old Jan 12, 2004 | 02:24 PM
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2 subs @ 4ohms? around 100x2 if I'm reading the info correctly
Old Jan 12, 2004 | 02:35 PM
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unless you run them parallel and get 200 to each
Old Jan 12, 2004 | 02:36 PM
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How do i wire it up like that? I have two terminals in the back of my box

[ January 12, 2004, 03:37 PM: Message edited by: DodgeShadow ]
Old Jan 12, 2004 | 03:31 PM
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If there is only one terminal, the subs are wired internally. You'll have to remove a sub from the box to access the wiring.
Old Jan 12, 2004 | 03:35 PM
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Oops, sorry, I thought you said you only had one terminal. If there are two terminals, you'll want to present the lowest possible load to the amplifier, which is 2ohm (Assuming you are using two 4ohm subs). Simply connect the positive to positive, and negative to negative between the two terminals, and run a single pair of wires to the amplifier. This will present a 2ohm mono load. The amplifier should provide around 400W RMS to split between the two subs. So each woofer should receive ~200watts.
Old Jan 12, 2004 | 03:49 PM
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The way u make it sound, it seems like id only be using one terminal. basically in the back of my box i have two of the black terminal cups. so i have 2 positive and 2 negative places to put wires. Im guessing i only have to use 1 of these?
Old Jan 12, 2004 | 04:28 PM
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no you attach wires to all four terminals, one to each of the four. so then you have four wires comming out of the back of your box. take the end of the two positives and twist them together and put it into the positive output of ur amp. do the same for the negative. the amp now sees a two ohm load which will give u 400rms, and 200 to each sub.

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