can someone explain this or point me in the right direction please?

 

this is the spec for my amp...

600 Watts @ 4 Ohms Bridged


how do i get a 4 ohm load and bridge my amp?

help please lol

 

ok...so i think i found out how to bridge, i use the left positive and the right negative. one from each channel right?

so how do i get a 4 ohm load out of that?

 

The amp puts out power into a load, it does not create the load. The load is determined by the speaker impedence in ohms and the number of speakers used. What speakers are you trying to hook up (model#, make) so we can check the impedence (list it if you know it)

 

im hooking up the amp to a pair of jl audio 12w3's

 

Still not quite enough info. These subs are available in a number of different voice coil configurations. Do you know what the configuration is of the subs you have. IE: SVC 4 ohm, DVC 2ohm, DVC 4ohm, DVC6ohm.

 

the 12w3's i have are dvc 4 ohms

 

2 Dual-4 Ohm Subwoofer with Voice Coils in Series=4 ohm load




[ September 15, 2004, 09:26 PM: Message edited by: Dann0 ]

 

Thanks dude, you beat me to it.

 

Straight from the JL wedsite. Nice [img]graemlins/thumb.gif[/img]