Will RCA Voltage Reduce If Splitting the Outputs To 2 Amps?
Question 1: 4 volt rca head unit going into an AudioControl EQL. The outputs on the EQL run to 2 separate ZPA amplifiers. Does this mean that the voltage output of the EQL (suppose it is 8 volts) is divided by 2 and each amplifier only sees 4 volts?
Question 2: What is the best solution to ensure each amplifier sees a full 8 volts?
Question 2: What is the best solution to ensure each amplifier sees a full 8 volts?
I am running ZPA amps which need a full 8 volts on the rca inputs to reach max power - esp. on the one driving my subs - I need max power and am trying to figure out a way other than running a line driver into each amp. [img]graemlins/dunno.gif[/img]
ps. I asked the same questions 1 and 2 on the Soundbuggy website and got the following respeonse: Question 1 is true, and for question 2, I'd say not to worry about it. But if you really feel you must, put a line driver between the EQ and the ZPA.
ps. I asked the same questions 1 and 2 on the Soundbuggy website and got the following respeonse: Question 1 is true, and for question 2, I'd say not to worry about it. But if you really feel you must, put a line driver between the EQ and the ZPA.
Ok, If you split your rca's, they will then be in a parallel circuit.
In a parallel the circuit the voltage in each branch is that same as the applied voltage.
In conclusion if you put a split on an 8 volt rca, each split would still have exactly 8 volts. No drop what so ever.
In a parallel the circuit the voltage in each branch is that same as the applied voltage.
In conclusion if you put a split on an 8 volt rca, each split would still have exactly 8 volts. No drop what so ever.
So then there shouldn't be an audible db reduction from the speakers connected to Amp#1 if I splice the RCAs (that provide the input signal to Amp#1) and have them run to Amp#2 as well. Right? :?: :?:
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^ Provided the supply has the current capability to supply that 8 volts into the additional load. 99% of the time this is not a problem but it does bear mentioning.
You have more chance of problems due to the actual physical Y-splitters than the voltage supply.
You have more chance of problems due to the actual physical Y-splitters than the voltage supply.
Originally posted by Dukk:
^ Provided the supply has the current capability to supply that 8 volts into the additional load. 99% of the time this is not a problem but it does bear mentioning.
You have more chance of problems due to the actual physical Y-splitters than the voltage supply.
^ Provided the supply has the current capability to supply that 8 volts into the additional load. 99% of the time this is not a problem but it does bear mentioning.
You have more chance of problems due to the actual physical Y-splitters than the voltage supply.
