I just bought a new kicker crv 12 2 ohm and i already had one so now i have two. But when i took my old one out of its box i relized that it was 4 ohms. Is it possible to run both of them one one amp? and if so How should i wire them?

 

no because they will see different power and work against each other.they will basically be out of phase. Both subs need to be the same impedance if their in a common chamber box.

 

something I'm not clear about here.. if he ran them parallel, you create a 3 ohm load... each coil would see the same power, they just contribute differently to the final resistance that the amp would recognize...

am I incorrect on this?

 

Each sub would receive a different amount of power, so one would play louder than the other and there would be significant cancellation. Can you exchange the sub for a 4 ohm model?

 

You are incorrect on that.
First of all, the combined load would NOT be 3 ohms (consider that two 4ohm speakers makes a 2 ohm load when wired parallel - you can bet that a 2ohm and a 4 will be less than 2ohm).

Here is how the math works. Write the impedance loads as a fraction
4 ohm = 4/1; 2 ohm = 2/1
Invert those fractions:
4/1 ~ 1/4; 2/1 ~ 1/2
Then add those numbers:
1/4 + 1/2 = 3/4
Take the final number and invert it.
3/4 = 4/3
This is your final load. Combining a 2ohm and a 4 ohm would give you a 1.3ohm final load.

That being said, the subs would not receive equal power. Roughly the 2ohm sub would receive 2/3rds of the power and the 4 ohm would receive 1/3 of the power. So if the subs aren't even receiving equal power from the amp, then they want be playing at the same volume (the amp doesn't care it only sees the final load - but basic electrical theory does care and the path of lesser resistance will take more of the power).

Wiring in Series would still have the same problem (although the math is easier for final impedance it would be 6 ohm) the subs wouls still have the 1/3 - 2/3 powerdistribution issue.

You simply can't mix those impedances on the same amp. Get a second amp and keep the subs in separate chambers and you'll be laughing.

My recommendation is to trade for a different coil if you can.

 

Every body missed it.

CVR's are dual voice coil. wanna do your math trick all over again?

Or just tell the OP no, don't waste your time. Spend 99 bucks to get the right one.

 

He didn't specify that they are DVC so then my math would be different.
However - he still has the same problem. My understanding of his post is that he bought the 2 ohm, and then realized he had a 4 ohm. So if he has the 4 ohm and CVR 's are DVC's he STILL HAS THE SAME PROBLEM - a dual 2 ohm sub and a dual 4 ohm sub.

The only way he could work it, is if he had a dual 2 ohm and a single 4ohm. He hasn't specified the voicecoil count on either sub. A reasonable assumption would be that his first sub is a CVR since he stated that he bought another. Then that would be a CVR dual 4.

So, here's my math trick again:

4 ohm = 4/1; 2 ohm = 2/1
Invert those fractions:
4/1 ~ 1/4; 2/1 ~ 1/2
Then add those numbers:
1/4 + 1/4 + 1/2 + 1/2 = 6/4
Take the final number and invert it.
6/4 = 4/6 = 2/3
This is your final load. 0.66 ohm final load.

Many amps will become a BBQ at that impedance - and you still have the issue of both subs receiving different amount of power.