Final load impedance for 3 subs
#1
Final load impedance for 3 subs
Hey, guys. I know that if I bridge 3 subs(single voice coil 4 ohms), I will get a final load of 1.33 ohms.
My question is - what would be the final load if I bridge 3 subs, but they are single voice coil 3.5 ohms each? And is there a place on-line, where I could use some sort of impedance calculator, so I won't have to bother anyone?
Thanks in advance
My question is - what would be the final load if I bridge 3 subs, but they are single voice coil 3.5 ohms each? And is there a place on-line, where I could use some sort of impedance calculator, so I won't have to bother anyone?
Thanks in advance
Last edited by Sasha; 03-30-2008 at 02:23 AM.
#3
To late to edit, but I should correct my terminology.
Coil impedance (ohms) divided by number of coils = final load on a parallel connections. Example 2 dual 2 ohm subs wired parallel = .5 ohm load and so on.
A series connection you simply add up the total of the coils to be wired in series.
Example 3 single 4ohm subs wire in series = 12ohms, but not that anybody would do that.
Coil impedance (ohms) divided by number of coils = final load on a parallel connections. Example 2 dual 2 ohm subs wired parallel = .5 ohm load and so on.
A series connection you simply add up the total of the coils to be wired in series.
Example 3 single 4ohm subs wire in series = 12ohms, but not that anybody would do that.
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