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Crossover freq. variance with impedance

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Old Jul 15, 2003 | 12:27 AM
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Let's say you're using a typical passive component crossover. Low pass for the mid lets say is 4000hz and the speaker in the set is 8ohm. What happen's to this crossover point when you swap in a 4ohm driver instead of the 8ohm?
Old Jul 15, 2003 | 06:57 AM
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Check the chart on page 16: http://www.rockfordfosgate.com/rftec...DSMamp_MAN.pdf

Pretty sure that your crossover point will be cut in half, so around 1800hz.
Old Jul 15, 2003 | 07:24 AM
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So would the same thing happen is you used 2 8 ohm speakers on the one crossover channel to create a 4 ohm load? Or will the frequencies still be cut in half?
Old Jul 15, 2003 | 07:29 AM
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The chart is on page 19 also! [img]smile.gif[/img]
Old Jul 15, 2003 | 01:14 PM
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www.the12volt.com is a cool place to hang out.
Old Jul 15, 2003 | 06:58 PM
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http://www.selectproducts.com/calculator_crossover.html [img]graemlins/thumb.gif[/img]
Old Jul 15, 2003 | 07:21 PM
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So it looks like the final cutoff would be 2000Hz with a 12db crossover. Would I be correct to say I could bypass the crossover and pick up a .22505mH inductor to get the desired 4000Hz cutoff? If so, could I find one at Radioshack or what other place?
Old Jul 16, 2003 | 04:43 PM
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Yeah check out the charts on the Solen site. Changing the resistance of the speaker drastically changes the x-over point.

Lardass.



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