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Ampliphier Voltage

Old Mar 31, 2004 | 07:42 PM
  #11  
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Originally posted by Gmac:
Not realy it ignores inuctive reactince. Even if the coil had an inductance of 0.005 heneries it would take the impediance of the coil up to 4.512 ohms at 80HZ and then
1000 = v^2/4.512
4512=v^2
V=67
I assumed 0.005 heneries and wich could be way off, i have been looking through ampliphier design procedure and am just trying to work throught the ampliphication stage and am woundering the amplitude of the final wave and to determine that I need to have an idea of the inductance of the coil
Power is determined by your voltage
amplifiers are considered voltage devices
the voltage remains the same
when the impedance increases current goes down
when current goes down so does power
Old Mar 31, 2004 | 08:48 PM
  #12  
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Originally posted by Half Time Immortal:
Power is determined by your voltage
amplifiers are considered voltage devices
the voltage remains the same
when the impedance increases current goes down
when current goes down so does power
All very true but put it does not answer the question.

Some one has to have an idea of what the inductance of a VC is on a sub.
Old Mar 31, 2004 | 09:39 PM
  #13  
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his current was at 1 ohm though... you're measuring 4 ohms.. current draw is proportional to the load resistance.. Current draw = Voltage/Resistance. Ahh, the joys of taking physics, makes all this stuff so much easier to understand [img]smile.gif[/img]
Old Mar 31, 2004 | 09:55 PM
  #15  
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Originally posted by bigmike216:
his current was at 1 ohm though... you're measuring 4 ohms.. current draw is proportional to the load resistance.. Current draw = Voltage/Resistance. Ahh, the joys of taking physics, makes all this stuff so much easier to understand [img]smile.gif[/img]
BigMike that is great for DC but ask in physics about inductive reactince and capacitive reactince, I used the same 2ohm coil he used I just accounted for the inductance the coil has.

Hey bigmike in physics have you covered the charging and discharing curves of inductors and capacitors when connected to a DC supply

[ March 31, 2004, 10:57 PM: Message edited by: Gmac ]
Old Mar 31, 2004 | 10:07 PM
  #16  
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Originally posted by dodgeram:
you voltage from the amp would stay at 44.7 volts no matter the impedance of the woofer , the current and therfore the power wouls drop


so if you were using the woofer example in your second post (4.512 ohms) on the same amp your power output would no longer be 1000 watts .......
so voltage and always stays the same, and you know your impedance

so your formula would have to be


44.7^2/4.15=power
power= 481 watts

if you wanna find out a woofers impedance at any given frequency you can play the tone you want and measure the speaker lead voltage and current (clamp on amp meter needed)

then you can calculate power and impedance with those 2 numbers
I looked at the top and I did not word my question correclty it should have been what would the voltage be if a amp was producing 1000W into a sub with a single VC rated ar 2ohms taking into consideration inductance.

Dodgeram you are most correct in the question I ha originaly asked because obviously it is assumed the power is rated at 2ohms.

Halftime
I now see what you were getting at

Sorry again I did not word my question correctly

Still does anyone know the approximate inductance of a VC on a sub?
Old Mar 31, 2004 | 10:51 PM
  #17  
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look at the ts specs for your woofer.. LE is inductance of the coil i believe.
Old Mar 31, 2004 | 11:26 PM
  #19  
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formula for inductive reactance - Xl = (2)(pi)(f)(L)

so if your coil had an inductance of 1.5 milihenries (0.0015 henries), and your frequency was 60Hz..

(2)(3.14)(60)(0.0015)

inductive reactance is .5652 ohms [img]smile.gif[/img]

Impedance and inductive reactance aren't the same thing.. formula for impedance:

(impedance)^2 = (resistance)^2 + (reactance)^2
or
Impedance = Sq Root of (resistance)^2 + (reactance)^2
or
Z = Sq Root of R^2 + X^2

so.. R = 2ohms
X = .5652 ohms

Z = Sq Root 2^2 + .5652^2
Z = 2.078

Z= your impedance at 60Hz [img]smile.gif[/img]

doesn't mean that's the number for your woofer.. but that would be the number if it had an inductance of 1.5 milihenries [img]smile.gif[/img]

[ April 01, 2004, 02:00 AM: Message edited by: bigmike216 ]
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