Matzilla

If i got 2 duel voice coil 6 ohm subs how would i hook them up to ahieve 2 or 4 ohm indipendence for the amp? is it possible?

2 8's AKA Jeepbeats

iTrader: (19)

Not with a single one, you can only achieve 3 ohms if each coil is wired in parallel to the other one, or 12 ohms if they are wired in series. With three of those subs you can wire them all together for a 4 ohm load or a 1 ohm load. Check out this for some more info on wiring subs: http://www.jlaudio.com/tutorials/wiring/index.html

[ November 07, 2004, 12:34 PM: Message edited by: Jeep ]

Fabe

You really can't, if you have only 2 dvc subs because you either have:

both coils parallel, subs parallel = 1.5 ohms
both coils parallel, subs series = 6 ohms
both coils series, subs parallel = 6 ohms
both coils series, subs series = 24 ohms

If you had three subs you could do it though...

What kind of amp do you have (power), which subs (power) and what do you want to get out of it?


Fabiano.

Coffeyman

correction....
actually i have 2 MA audio dual 6 ohm 12'' subs. when you work out the ACTUAL math, wiring all in parallel, it comes out to 1.6666666666.... ohms. it's not 1.5 and it's not 2 but it's a pretty good resistance for most amps to run around RMS power.

2 8's AKA Jeepbeats

iTrader: (19)

The impedance will never read bang on with speakers usually, i.e. a 4 ohm sub may give you a 3.6 ohm reading. Also have to remember that impedance varies with frequency too.....

King Dynasty

iTrader: (-1)

TRUE that JEEP , most of the time people dont run 6ohm subs unless they have more than 3 subs , i used to run 3 X15 @ 1 ohm they were all 6ohms

Get a MM and check your coils u might be lucky and get near 2 ohms

Rockney

I run a pair of DVC 6's, get a 1ohm stable amp and run it nice and stable @ 1.5ohm. [img]smile.gif[/img] , I guess im different.

maltesechicken

Here is the ACTUAL math:
6 + 6 + 6 + 6 (Reciprocate fraction)
1/6 + 1/6 + 1/6 + 1/6 = 4/6 (Reciprocate fraction)
6/4 = 1 2/4 = 1.5 ohms

I dunno, my actual math comes out to 1.5 ohms. What is your actual math? or are you using a DMM. If you are using a DMM do you realize that is showing you resistance NOT impedance?